Happy belated Earth Day! The Earth might be doomed, but you can still save your LSAT score.

We may be a day late and a dollar short, but in honor of the Earth Day yesterday, MSS is happy to bring you an organic, locally sourced, and reusable LSAT Logic Game! Give it a try, and think of it as penance for your high carbon lifestyle.

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**Three recycling centers, A, B, and C, will each recycle at least one type of material: P, Q, R, and S. The assignment of materials to centers will adhere to the following rules:**

Each material will be recycled by at least one recycling center.

B recycles any material recycled by A.

Material Q is recycled by at most one recycling center.

P is recycled at a center if but only if R is recycled at the same center.

B and C cannot recycle the same materials.

C recycles S.

*1. How many of the materials must be recycled at exactly one center?*

(A) 0

(B) 1

(C) 2

(D) 3

(E) 4

*2. Which one of the following is a complete and accurate list of the materials that can be recycled at all three centers?*

(A) None

(B) P, R

(C) P, S

(D) P, R, S

(E) P, R, Q

*3. Which one of the following could be true?*

(A) P is recycled at center C, and R is recycled at center B.

(B) C is the only center that recycles P.

(C) B is the only center that recycles Q.

(D) S and R are recycled at the same center.

(E) C recycles all four materials.

*4. If A recycles R, and S is not recycled at the same center as P, then which one of the following must be true?*

(A) C recycles exactly one type of material.

(B) S is recycled at more centers than Q.

(C) Q and S are recycled at the same center.

(D) B recycles more materials than A.

(E) A recycles exactly two types of materials.

*5. Which one of the following must be false?*

(A) A recycles exactly two types of materials.

(B) B recycles Q.

(C) C recycles R.

(D) C recycles Q.

(E) P is recycled at two recycling centers.

*6. Which one of the following could be a complete and accurate assignment of materials to centers?*

(A) A: P; B: P, R; C: Q, S

(B) A: S; B: P, R; C: Q, S

(C) A: P, R; B: P, R; C: S

(D) A: P, R, Q; B: P, R; C: S

(E) A: P, R; B: P, R, Q; C: S

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*Hints:*

1. There’s a principle of distribution hidden in the intro.

2. Represent rule 2 correctly. “Any” is a sufficient condition indicator.

3. Combine rules 1 and 3. Then combine the result with rule 2.

4. Combine rules 5 and 6. Then combine the result with the contrapositive of rule 2.

5. Create scenarios based on rule 4.

*(Answer Key: 1: C; 2: A; 3: C; 4: E; 5: C; 6: E)*

*A version of this post was originally published on 4/22/14.*